❮ Math Methods
Example
System.out.println(Math.expm1(0));
System.out.println(Math.expm1(1));
System.out.println(Math.expm1(10));
System.out.println(Math.expm1(4.8));
System.out.println(Math.expm1(Math.E));Definition and Usage
The expm1() method returns the solution to e x - 1 for any number x.
e is the base of the natural system of logarithms (approximately 2.718282). In Java, the value of e is available as the constant Math.E .
Syntax
public static double expm1(double
number )Parameter Values
| Parameter | Description |
|---|---|
| number | Required. The value of x in the formula e x - 1. |
Technical Details
| Returns: | A double value representing the solution to e x - 1 for a number x. |
|---|---|
| Java version: | 1.5+ |