Flash cards
Review the key moves
1/4
Core idea
What is the main idea behind Java Math expm1() Method?
Lesson checks
Practice each idea before moving on
Short Mimo-style checks built from this lesson's code, terms, and sequence.
1Quick choice
Which statement best captures the main point of this lesson?
2Fill blank
Complete the missing token from the example code.
___.out.println(Math.expm1(0));3Order
Put the learning moves in the order that makes the concept easiest to apply.
The expm1() method returns the solution to e x - 1 for any number x.
Definition and Usage
Java Math expm1() Method
❮ Math Methods
Example
System.out.println(Math.expm1(0));
System.out.println(Math.expm1(1));
System.out.println(Math.expm1(10));
System.out.println(Math.expm1(4.8));
System.out.println(Math.expm1(Math.E));Definition and Usage
The expm1() method returns the solution to e x - 1 for any number x.
e is the base of the natural system of logarithms (approximately 2.718282). In Java, the value of e is available as the constant Math.E .
Syntax
public static double expm1(double
number )Parameter Values
| Parameter | Description |
|---|---|
| number | Required. The value of x in the formula e x - 1. |
Technical Details
| Returns: | A double value representing the solution to e x - 1 for a number x. |
|---|---|
| Java version: | 1.5+ |